-- Migrated from DuckDB test: test/sql/join/full_outer/ complex tests -- Tests complex outer join scenarios CREATE TABLE employees(emp_id INTEGER, "name" VARCHAR, dept_id INTEGER, salary INTEGER, ts TIMESTAMP TIME INDEX); Affected Rows: 0 CREATE TABLE departments(dept_id INTEGER, dept_name VARCHAR, manager_id INTEGER, ts TIMESTAMP TIME INDEX); Affected Rows: 0 CREATE TABLE projects(proj_id INTEGER, proj_name VARCHAR, dept_id INTEGER, budget INTEGER, ts TIMESTAMP TIME INDEX); Affected Rows: 0 INSERT INTO employees VALUES (1, 'Alice', 10, 75000, 1000), (2, 'Bob', 20, 65000, 2000), (3, 'Charlie', 10, 80000, 3000), (4, 'Diana', 30, 70000, 4000), (5, 'Eve', NULL, 60000, 5000); Affected Rows: 5 INSERT INTO departments VALUES (10, 'Engineering', 1, 1000), (20, 'Marketing', 2, 2000), (40, 'HR', NULL, 3000); Affected Rows: 3 INSERT INTO projects VALUES (101, 'ProjectA', 10, 100000, 1000), (102, 'ProjectB', 20, 150000, 2000), (103, 'ProjectC', 30, 75000, 3000), (104, 'ProjectD', 50, 200000, 4000); Affected Rows: 4 -- Full outer join with multiple conditions SELECT e.emp_id, e."name", d.dept_id, d.dept_name FROM employees e FULL OUTER JOIN departments d ON e.dept_id = d.dept_id ORDER BY e.emp_id, d.dept_id; +--------+---------+---------+-------------+ | emp_id | name | dept_id | dept_name | +--------+---------+---------+-------------+ | 1 | Alice | 10 | Engineering | | 2 | Bob | 20 | Marketing | | 3 | Charlie | 10 | Engineering | | 4 | Diana | | | | 5 | Eve | | | | | | 40 | HR | +--------+---------+---------+-------------+ -- Left outer join with IS NULL filter SELECT e.emp_id, e."name", e.dept_id, d.dept_name FROM employees e LEFT OUTER JOIN departments d ON e.dept_id = d.dept_id WHERE d.dept_id IS NULL ORDER BY e.emp_id; +--------+-------+---------+-----------+ | emp_id | name | dept_id | dept_name | +--------+-------+---------+-----------+ | 4 | Diana | 30 | | | 5 | Eve | | | +--------+-------+---------+-----------+ -- Right outer join SELECT e.emp_id, e."name", d.dept_id, d.dept_name FROM employees e RIGHT OUTER JOIN departments d ON e.dept_id = d.dept_id ORDER BY d.dept_id, e.emp_id; +--------+---------+---------+-------------+ | emp_id | name | dept_id | dept_name | +--------+---------+---------+-------------+ | 1 | Alice | 10 | Engineering | | 3 | Charlie | 10 | Engineering | | 2 | Bob | 20 | Marketing | | | | 40 | HR | +--------+---------+---------+-------------+ -- Triple outer join SELECT e."name", d.dept_name, p.proj_name, p.budget FROM employees e FULL OUTER JOIN departments d ON e.dept_id = d.dept_id FULL OUTER JOIN projects p ON d.dept_id = p.dept_id ORDER BY e.emp_id, p.proj_id; +---------+-------------+-----------+--------+ | name | dept_name | proj_name | budget | +---------+-------------+-----------+--------+ | Alice | Engineering | ProjectA | 100000 | | Bob | Marketing | ProjectB | 150000 | | Charlie | Engineering | ProjectA | 100000 | | Diana | | | | | Eve | | | | | | | ProjectC | 75000 | | | | ProjectD | 200000 | | | HR | | | +---------+-------------+-----------+--------+ -- Outer join with aggregation SELECT d.dept_name, COUNT(e.emp_id) as employee_count, AVG(e.salary) as avg_salary, SUM(p.budget) as total_project_budget FROM departments d LEFT OUTER JOIN employees e ON d.dept_id = e.dept_id LEFT OUTER JOIN projects p ON d.dept_id = p.dept_id GROUP BY d.dept_name ORDER BY d.dept_name; +-------------+----------------+------------+----------------------+ | dept_name | employee_count | avg_salary | total_project_budget | +-------------+----------------+------------+----------------------+ | Engineering | 2 | 77500.0 | 200000 | | HR | 0 | | | | Marketing | 1 | 65000.0 | 150000 | +-------------+----------------+------------+----------------------+ DROP TABLE employees; Affected Rows: 0 DROP TABLE departments; Affected Rows: 0 DROP TABLE projects; Affected Rows: 0