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https://github.com/GreptimeTeam/greptimedb.git
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eea8b1c730
* feat: add vec_kth_elem function Signed-off-by: pikady <2652917633@qq.com> * code format Signed-off-by: pikady <2652917633@qq.com> * add test sql Signed-off-by: pikady <2652917633@qq.com> * change indexing from 1-based to 0-based Signed-off-by: pikady <2652917633@qq.com> * improve code formatting and correct spelling errors Signed-off-by: pikady <2652917633@qq.com> * Update tests/cases/standalone/common/function/vector/vector.sql I noticed the two lines are identical. Could you clarify the reason for the change? Thanks! Co-authored-by: Zhenchi <zhongzc_arch@outlook.com> --------- Signed-off-by: pikady <2652917633@qq.com> Co-authored-by: Zhenchi <zhongzc_arch@outlook.com>
136 lines
3.6 KiB
SQL
136 lines
3.6 KiB
SQL
SELECT vec_to_string(parse_vec('[1.0, 2.0]'));
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SELECT vec_to_string(parse_vec('[1.0, 2.0, 3.0]'));
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SELECT vec_to_string(parse_vec('[]'));
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SELECT vec_to_string(vec_add('[1.0, 2.0]', '[3.0, 4.0]'));
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SELECT vec_to_string(vec_add(parse_vec('[1.0, 2.0]'), '[3.0, 4.0]'));
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SELECT vec_to_string(vec_add('[1.0, 2.0]', parse_vec('[3.0, 4.0]')));
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SELECT vec_to_string(vec_mul('[1.0, 2.0]', '[3.0, 4.0]'));
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SELECT vec_to_string(vec_mul(parse_vec('[1.0, 2.0]'), '[3.0, 4.0]'));
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SELECT vec_to_string(vec_mul('[1.0, 2.0]', parse_vec('[3.0, 4.0]')));
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SELECT vec_to_string(vec_sub('[1.0, 1.0]', '[1.0, 2.0]'));
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SELECT vec_to_string(vec_sub('[-1.0, -1.0]', '[1.0, 2.0]'));
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SELECT vec_to_string(vec_sub('[1.0, 1.0]', parse_vec('[1.0, 2.0]')));
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SELECT vec_to_string(vec_sub('[-1.0, -1.0]', parse_vec('[1.0, 2.0]')));
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SELECT vec_to_string(vec_sub(parse_vec('[1.0, 1.0]'), '[1.0, 2.0]'));
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SELECT vec_to_string(vec_sub(parse_vec('[-1.0, -1.0]'), '[1.0, 2.0]'));
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SELECT vec_elem_sum('[1.0, 2.0, 3.0]');
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SELECT vec_elem_sum('[-1.0, -2.0, -3.0]');
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SELECT vec_elem_sum(parse_vec('[1.0, 2.0, 3.0]'));
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SELECT vec_elem_sum(parse_vec('[-1.0, -2.0, -3.0]'));
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SELECT vec_to_string(vec_div('[1.0, 2.0]', '[3.0, 4.0]'));
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SELECT vec_to_string(vec_div(parse_vec('[1.0, 2.0]'), '[3.0, 4.0]'));
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SELECT vec_to_string(vec_div('[1.0, 2.0]', parse_vec('[3.0, 4.0]')));
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SELECT vec_to_string(vec_div('[1.0, -2.0]', parse_vec('[0.0, 0.0]')));
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SELECT vec_elem_product('[1.0, 2.0, 3.0, 4.0]');
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SELECT vec_elem_product('[-1.0, -2.0, -3.0, 4.0]');
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SELECT vec_elem_product(parse_vec('[1.0, 2.0, 3.0, 4.0]'));
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SELECT vec_elem_product(parse_vec('[-1.0, -2.0, -3.0, 4.0]'));
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SELECT vec_to_string(vec_norm('[0.0, 2.0, 3.0]'));
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SELECT vec_to_string(vec_norm('[1.0, 2.0, 3.0]'));
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SELECT vec_to_string(vec_norm('[7.0, 8.0, 9.0]'));
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SELECT vec_to_string(vec_norm('[7.0, -8.0, 9.0]'));
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SELECT vec_to_string(vec_norm(parse_vec('[7.0, -8.0, 9.0]')));
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SELECT vec_to_string(vec_sum(v))
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FROM (
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SELECT '[1.0, 2.0, 3.0]' AS v
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UNION ALL
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SELECT '[-1.0, -2.0, -3.0]' AS v
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UNION ALL
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SELECT '[4.0, 5.0, 6.0]' AS v
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);
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SELECT vec_to_string(vec_product(v))
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FROM (
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SELECT '[1.0, 2.0, 3.0]' AS v
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UNION ALL
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SELECT '[-1.0, -2.0, -3.0]' AS v
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UNION ALL
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SELECT '[4.0, 5.0, 6.0]' AS v
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);
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SELECT vec_dim('[7.0, 8.0, 9.0, 10.0]');
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SELECT v, vec_dim(v)
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FROM (
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SELECT '[1.0, 2.0, 3.0]' AS v
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UNION ALL
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SELECT '[-1.0]' AS v
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UNION ALL
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SELECT '[4.0, 5.0, 6.0]' AS v
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) Order By vec_dim(v) ASC;
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SELECT v, vec_dim(v)
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FROM (
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SELECT '[1.0, 2.0, 3.0]' AS v
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UNION ALL
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SELECT '[-1.0]' AS v
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UNION ALL
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SELECT '[7.0, 8.0, 9.0, 10.0]' AS v
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) Order By vec_dim(v) ASC;
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SELECT vec_kth_elem('[1.0, 2.0, 3.0]', 2);
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SELECT v, vec_kth_elem(v, 0) AS first_elem
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FROM (
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SELECT '[1.0, 2.0, 3.0]' AS v
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UNION ALL
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SELECT '[4.0, 5.0, 6.0, 7.0]' AS v
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UNION ALL
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SELECT '[8.0]' AS v
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)
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WHERE vec_kth_elem(v, 0) > 2.0;
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SELECT vec_to_string(vec_subvector('[1.0,2.0,3.0,4.0,5.0]', 0, 3));
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SELECT vec_to_string(vec_subvector('[1.0,2.0,3.0,4.0,5.0]', 5, 5));
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SELECT v, vec_to_string(vec_subvector(v, 3, 5))
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FROM (
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SELECT '[1.0, 2.0, 3.0, 4.0, 5.0]' AS v
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UNION ALL
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SELECT '[-1.0, -2.0, -3.0, -4.0, -5.0, -6.0]' AS v
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UNION ALL
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SELECT '[4.0, 5.0, 6.0, 10, -8, 100]' AS v
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) ORDER BY v;
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SELECT vec_to_string(vec_subvector(v, 0, 5))
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FROM (
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SELECT '[1.1, 2.2, 3.3, 4.4, 5.5]' AS v
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UNION ALL
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SELECT '[-1.1, -2.1, -3.1, -4.1, -5.1, -6.1]' AS v
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UNION ALL
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SELECT '[4.0, 5.0, 6.0, 10, -8, 100]' AS v
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) ORDER BY v;
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